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Find the minimum value of the function f(x) = 2x^2 - 8x + 10. (2022)

Practice Questions

1 question
Q1
Find the minimum value of the function f(x) = 2x^2 - 8x + 10. (2022)
  1. 2
  2. 4
  3. 6
  4. 8

Questions & Step-by-step Solutions

1 item
Q
Q: Find the minimum value of the function f(x) = 2x^2 - 8x + 10. (2022)
Solution: The minimum occurs at x = 2. f(2) = 2(2^2) - 8(2) + 10 = 6.
Steps: 0

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