If the cost function is C(x) = 3x^2 + 12x + 5, find the minimum cost. (2020)

Practice Questions

Q1
If the cost function is C(x) = 3x^2 + 12x + 5, find the minimum cost. (2020)
  1. 5
  2. 8
  3. 12
  4. 10

Questions & Step-by-Step Solutions

If the cost function is C(x) = 3x^2 + 12x + 5, find the minimum cost. (2020)
  • Step 1: Identify the cost function, which is C(x) = 3x^2 + 12x + 5.
  • Step 2: Recognize that this is a quadratic function in the form of ax^2 + bx + c, where a = 3, b = 12, and c = 5.
  • Step 3: To find the minimum cost, use the formula for the x-coordinate of the vertex of a parabola, which is x = -b/(2a).
  • Step 4: Substitute the values of a and b into the formula: x = -12/(2*3).
  • Step 5: Calculate the denominator: 2*3 = 6.
  • Step 6: Now calculate x: x = -12/6 = -2.
  • Step 7: To find the minimum cost, substitute x = -2 back into the cost function C(x).
  • Step 8: Calculate C(-2): C(-2) = 3(-2)^2 + 12(-2) + 5.
  • Step 9: Calculate (-2)^2 = 4, so C(-2) = 3*4 + 12*(-2) + 5.
  • Step 10: Now calculate: 3*4 = 12, and 12*(-2) = -24.
  • Step 11: Combine the results: C(-2) = 12 - 24 + 5.
  • Step 12: Finally, calculate: 12 - 24 = -12, and -12 + 5 = -7.
  • Quadratic Functions – Understanding the properties of quadratic functions, including how to find their minimum or maximum values using the vertex formula.
  • Cost Functions – Applying mathematical concepts to real-world scenarios, specifically in determining minimum costs based on a given cost function.
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