What is the freezing point depression of a solution containing 1 mol of NaCl in

What is the freezing point depression of a solution containing 1 mol of NaCl in 1 kg of water? (Kf for water = 1.86 °C kg/mol) (2023)

What is the freezing point depression of a solution containing 1 mol of NaCl in 1 kg of water? (Kf for water = 1.86 °C kg/mol) (2023)

Step 1: Identify the formula for freezing point depression, which is ΔTf = i * Kf * m.
Step 2: Determine the van 't Hoff factor (i) for NaCl. Since NaCl dissociates into two ions (Na+ and Cl-), i = 2.
Step 3: Identify the cryoscopic constant (Kf) for water, which is given as 1.86 °C kg/mol.
Step 4: Determine the molality (m) of the solution. Since there is 1 mol of NaCl in 1 kg of water, m = 1 mol/kg.
Step 5: Plug the values into the formula: ΔTf = 2 * 1.86 °C kg/mol * 1.
Step 6: Calculate the freezing point depression: ΔTf = 2 * 1.86 = 3.72 °C.

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