What is the molarity of a solution prepared by dissolving 5 grams of NaCl in eno
Practice Questions
Q1
What is the molarity of a solution prepared by dissolving 5 grams of NaCl in enough water to make 250 mL of solution? (Molar mass of NaCl = 58.5 g/mol) (2023)
0.34 M
0.42 M
0.25 M
0.50 M
Questions & Step-by-Step Solutions
What is the molarity of a solution prepared by dissolving 5 grams of NaCl in enough water to make 250 mL of solution? (Molar mass of NaCl = 58.5 g/mol) (2023)
Step 1: Identify the mass of NaCl you have, which is 5 grams.
Step 2: Find the molar mass of NaCl, which is given as 58.5 g/mol.
Step 3: Calculate the number of moles of NaCl using the formula: moles = mass (g) / molar mass (g/mol). So, moles of NaCl = 5 g / 58.5 g/mol.
Step 4: Perform the calculation: 5 g / 58.5 g/mol = 0.0855 moles of NaCl.
Step 5: Convert the volume of the solution from milliliters to liters. Since 250 mL = 0.250 L.
Step 6: Use the molarity formula: Molarity (M) = moles of solute / liters of solution. Substitute the values: M = 0.0855 moles / 0.250 L.
Step 7: Perform the calculation: 0.0855 moles / 0.250 L = 0.342 M.
Step 8: Round the answer to two decimal places, which gives approximately 0.34 M.
