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What is the equivalent resistance of two resistors, R1 = 6Ω and R2 = 3Ω, in para
What is the equivalent resistance of two resistors, R1 = 6Ω and R2 = 3Ω, in parallel?
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What is the equivalent resistance of two resistors, R1 = 6Ω and R2 = 3Ω, in parallel?
2Ω
4Ω
9Ω
18Ω
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The formula for equivalent resistance in parallel is 1/R_eq = 1/R1 + 1/R2. Thus, 1/R_eq = 1/6 + 1/3 = 1/2, so R_eq = 2Ω.
Questions & Step-by-step Solutions
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Q: What is the equivalent resistance of two resistors, R1 = 6Ω and R2 = 3Ω, in parallel?
Solution:
The formula for equivalent resistance in parallel is 1/R_eq = 1/R1 + 1/R2. Thus, 1/R_eq = 1/6 + 1/3 = 1/2, so R_eq = 2Ω.
Steps: 8
Show Steps
Step 1: Identify the values of the resistors. Here, R1 = 6Ω and R2 = 3Ω.
Step 2: Write down the formula for equivalent resistance in parallel: 1/R_eq = 1/R1 + 1/R2.
Step 3: Substitute the values of R1 and R2 into the formula: 1/R_eq = 1/6 + 1/3.
Step 4: Find a common denominator to add the fractions. The common denominator for 6 and 3 is 6.
Step 5: Rewrite 1/3 as 2/6, so now we have: 1/R_eq = 1/6 + 2/6.
Step 6: Add the fractions: 1/R_eq = (1 + 2)/6 = 3/6.
Step 7: Simplify 3/6 to 1/2, so now we have: 1/R_eq = 1/2.
Step 8: To find R_eq, take the reciprocal of 1/2: R_eq = 2Ω.
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