A simple pendulum oscillates with a period of 2 seconds. What is the length of the pendulum? (2021)
Practice Questions
1 question
Q1
A simple pendulum oscillates with a period of 2 seconds. What is the length of the pendulum? (2021)
0.5 m
1 m
2 m
4 m
The period T of a simple pendulum is given by T = 2π√(L/g). Rearranging gives L = (T^2 * g) / (4π^2). Using g = 9.8 m/s² and T = 2 s, we find L = (2^2 * 9.8) / (4π^2) ≈ 1 m.
Questions & Step-by-step Solutions
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Q
Q: A simple pendulum oscillates with a period of 2 seconds. What is the length of the pendulum? (2021)
Solution: The period T of a simple pendulum is given by T = 2π√(L/g). Rearranging gives L = (T^2 * g) / (4π^2). Using g = 9.8 m/s² and T = 2 s, we find L = (2^2 * 9.8) / (4π^2) ≈ 1 m.
