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A simple pendulum oscillates with a period of 2 seconds. What is the length of t
Practice Questions
Q1
A simple pendulum oscillates with a period of 2 seconds. What is the length of the pendulum? (2021)
0.5 m
1 m
2 m
4 m
Questions & Step-by-Step Solutions
A simple pendulum oscillates with a period of 2 seconds. What is the length of the pendulum? (2021)
Steps
Concepts
Step 1: Understand the formula for the period of a simple pendulum, which is T = 2π√(L/g).
Step 2: Rearrange the formula to solve for L (length of the pendulum). The rearranged formula is L = (T^2 * g) / (4π^2).
Step 3: Identify the values needed for the calculation. We have T = 2 seconds and g = 9.8 m/s².
Step 4: Substitute the values into the rearranged formula: L = (2^2 * 9.8) / (4π^2).
Step 5: Calculate 2^2, which is 4.
Step 6: Multiply 4 by 9.8 to get 39.2.
Step 7: Calculate 4π^2. First, find π (approximately 3.14), then square it to get about 9.86, and finally multiply by 4 to get approximately 39.44.
Step 8: Divide 39.2 by 39.44 to find L. This gives approximately 1 meter.
Simple Pendulum Period
– The relationship between the period of a simple pendulum and its length, derived from the formula T = 2π√(L/g).
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