Solve the differential equation y'' - 3y' + 2y = 0.

Practice Questions

Q1
Solve the differential equation y'' - 3y' + 2y = 0.
  1. y = C1e^(2x) + C2e^(x)
  2. y = C1e^(x) + C2e^(2x)
  3. y = C1e^(-x) + C2e^(-2x)
  4. y = C1e^(3x) + C2e^(x)

Questions & Step-by-Step Solutions

Solve the differential equation y'' - 3y' + 2y = 0.
  • Step 1: Identify the given differential equation: y'' - 3y' + 2y = 0.
  • Step 2: Write the characteristic equation by replacing y'' with r^2, y' with r, and y with 1: r^2 - 3r + 2 = 0.
  • Step 3: Factor the characteristic equation: (r - 1)(r - 2) = 0.
  • Step 4: Solve for r by setting each factor to zero: r - 1 = 0 gives r = 1, and r - 2 = 0 gives r = 2.
  • Step 5: Write the general solution using the values of r: y = C1 * e^(1x) + C2 * e^(2x), where C1 and C2 are constants.
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