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Determine the minimum value of f(x) = x^2 - 4x + 5. (2021)

Practice Questions

1 question
Q1
Determine the minimum value of f(x) = x^2 - 4x + 5. (2021)
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Questions & Step-by-step Solutions

1 item
Q
Q: Determine the minimum value of f(x) = x^2 - 4x + 5. (2021)
Solution: The vertex form gives the minimum at x = 2. f(2) = 2^2 - 4(2) + 5 = 1.
Steps: 0

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