What is the minimum value of the function f(x) = 4x^2 - 16x + 20? (2021) 2021

Practice Questions

1 question
Q1
What is the minimum value of the function f(x) = 4x^2 - 16x + 20? (2021) 2021
  1. 4
  2. 5
  3. 6
  4. 3

Questions & Step-by-step Solutions

1 item
Q
Q: What is the minimum value of the function f(x) = 4x^2 - 16x + 20? (2021) 2021
Solution: The vertex occurs at x = 2. f(2) = 4(2^2) - 16(2) + 20 = 4.
Steps: 0

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