If 20 grams of glucose (C6H12O6) is dissolved in 1 liter of water, what is the m

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Question: If 20 grams of glucose (C6H12O6) is dissolved in 1 liter of water, what is the molarity of the solution? (Molar mass of glucose = 180 g/mol) (2020) 2020

Options:

0.11 M
0.5 M
0.2 M
0.33 M

Correct Answer: 0.11 M

Exam Year: 2020

Solution:

Moles of glucose = 20 g / 180 g/mol = 0.111 M. Molarity = 0.111 moles / 1 L = 0.11 M.

If 20 grams of glucose (C6H12O6) is dissolved in 1 liter of water, what is the m

Practice Questions

If 20 grams of glucose (C6H12O6) is dissolved in 1 liter of water, what is the molarity of the solution? (Molar mass of glucose = 180 g/mol) (2020) 2020

0.11 M
0.5 M
0.2 M
0.33 M

Questions & Step-by-Step Solutions

If 20 grams of glucose (C6H12O6) is dissolved in 1 liter of water, what is the molarity of the solution? (Molar mass of glucose = 180 g/mol) (2020) 2020

Step 1: Identify the mass of glucose you have, which is 20 grams.
Step 2: Find the molar mass of glucose, which is given as 180 g/mol.
Step 3: Calculate the number of moles of glucose using the formula: Moles = Mass (g) / Molar Mass (g/mol). So, Moles of glucose = 20 g / 180 g/mol.
Step 4: Perform the calculation: 20 divided by 180 equals approximately 0.111 moles of glucose.
Step 5: Identify the volume of the solution, which is 1 liter.
Step 6: Calculate the molarity using the formula: Molarity (M) = Moles of solute / Volume of solution (L). So, Molarity = 0.111 moles / 1 L.
Step 7: Perform the calculation: 0.111 divided by 1 equals 0.111 M.

Molarity Calculation – Molarity is calculated by dividing the number of moles of solute by the volume of solution in liters.
Moles and Molar Mass – Understanding how to convert grams of a substance to moles using its molar mass.

If 20 grams of glucose (C6H12O6) is dissolved in 1 liter of water, what is the m

What’s inside this PDF?

If 20 grams of glucose (C6H12O6) is dissolved in 1 liter of water, what is the m

Practice Questions

Questions & Step-by-Step Solutions

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