How many grams of KCl are needed to prepare 250 mL of a 0.5 M solution? (2023) 2

Practice Questions

Q1
How many grams of KCl are needed to prepare 250 mL of a 0.5 M solution? (2023) 2023
  1. 7.45 g
  2. 12.5 g
  3. 9.25 g
  4. 5.25 g

Questions & Step-by-Step Solutions

How many grams of KCl are needed to prepare 250 mL of a 0.5 M solution? (2023) 2023
  • Step 1: Understand that Molarity (M) is the number of moles of solute per liter of solution.
  • Step 2: Convert the volume from milliliters to liters. 250 mL is equal to 0.25 L.
  • Step 3: Identify the molar mass of KCl, which is 74.55 g/mol.
  • Step 4: Use the formula to find the grams needed: Grams = Molarity * Volume (L) * Molar mass.
  • Step 5: Plug in the values: Grams = 0.5 M * 0.25 L * 74.55 g/mol.
  • Step 6: Calculate the result: Grams = 0.5 * 0.25 * 74.55 = 9.31 g.
  • Molarity Calculation – Understanding how to calculate the amount of solute needed based on molarity, volume, and molar mass.
  • Unit Conversion – Converting volume from mL to L to use in molarity calculations.
  • Molar Mass – Using the correct molar mass of KCl to find the mass needed for the solution.
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