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How many grams of KCl are needed to prepare 250 mL of a 0.5 M solution? (2023) 2023

Practice Questions

1 question
Q1
How many grams of KCl are needed to prepare 250 mL of a 0.5 M solution? (2023) 2023
  1. 7.45 g
  2. 12.5 g
  3. 9.25 g
  4. 5.25 g

Questions & Step-by-step Solutions

1 item
Q
Q: How many grams of KCl are needed to prepare 250 mL of a 0.5 M solution? (2023) 2023
Solution: Molar mass of KCl = 74.55 g/mol. Grams = Molarity * Volume (L) * Molar mass = 0.5 M * 0.25 L * 74.55 g/mol = 9.31 g.
Steps: 0

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