What is the oxidation state of chlorine in NaClO3? (2022) 2022
Practice Questions
1 question
Q1
What is the oxidation state of chlorine in NaClO3? (2022) 2022
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In NaClO3, the oxidation state of chlorine is +5. Sodium is +1 and each oxygen is -2, leading to the equation: +1 + x + 3(-2) = 0, solving gives x = +5.
Questions & Step-by-step Solutions
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Q
Q: What is the oxidation state of chlorine in NaClO3? (2022) 2022
Solution: In NaClO3, the oxidation state of chlorine is +5. Sodium is +1 and each oxygen is -2, leading to the equation: +1 + x + 3(-2) = 0, solving gives x = +5.
Steps: 6
Step 1: Identify the compound. We have NaClO3, which consists of sodium (Na), chlorine (Cl), and oxygen (O).
Step 2: Assign known oxidation states. Sodium (Na) has an oxidation state of +1. Each oxygen (O) has an oxidation state of -2.
Step 3: Write the equation for the sum of oxidation states. The total oxidation states must equal 0 because the compound is neutral. The equation is: +1 (for Na) + x (for Cl) + 3(-2) (for 3 O) = 0.
Step 4: Simplify the equation. This becomes: +1 + x - 6 = 0.
Step 5: Solve for x. Rearranging gives x = 6 - 1, which simplifies to x = +5.
Step 6: Conclude that the oxidation state of chlorine (Cl) in NaClO3 is +5.
