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What is the oxidation state of sulfur in H2SO4? (2021) 2021

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Question: What is the oxidation state of sulfur in H2SO4? (2021) 2021

Options:

  1. +6
  2. +4
  3. +2
  4. 0

Correct Answer: +6

Exam Year: 2021

Solution: 

In H2SO4, the oxidation state of sulfur is +6. Each hydrogen is +1 and each oxygen is -2, leading to the equation: 2(+1) + x + 4(-2) = 0, solving gives x = +6.

What is the oxidation state of sulfur in H2SO4? (2021) 2021

Practice Questions

Q1
What is the oxidation state of sulfur in H2SO4? (2021) 2021
  1. +6
  2. +4
  3. +2
  4. 0

Questions & Step-by-Step Solutions

What is the oxidation state of sulfur in H2SO4? (2021) 2021
  • Step 1: Identify the chemical formula. We have H2SO4, which contains hydrogen (H), sulfur (S), and oxygen (O).
  • Step 2: Determine the oxidation states of known elements. Hydrogen (H) has an oxidation state of +1, and oxygen (O) has an oxidation state of -2.
  • Step 3: Count the number of each type of atom in H2SO4. There are 2 hydrogen atoms, 1 sulfur atom, and 4 oxygen atoms.
  • Step 4: Write the equation for the sum of oxidation states. The equation is: 2(+1) + x + 4(-2) = 0, where x is the oxidation state of sulfur.
  • Step 5: Calculate the contributions from hydrogen and oxygen. 2(+1) = +2 and 4(-2) = -8.
  • Step 6: Substitute these values into the equation: +2 + x - 8 = 0.
  • Step 7: Simplify the equation: x - 6 = 0.
  • Step 8: Solve for x: x = +6.
  • Step 9: Conclude that the oxidation state of sulfur in H2SO4 is +6.
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