What is the oxidation state of chromium in K2Cr2O7? (2021) 2021
Practice Questions
1 question
Q1
What is the oxidation state of chromium in K2Cr2O7? (2021) 2021
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+6
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In K2Cr2O7, the total charge from potassium (K) is +2, and oxygen (O) contributes -14. Let the oxidation state of Cr be x. The equation is 2x - 14 + 2 = 0, solving gives x = +6.
Questions & Step-by-step Solutions
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Q
Q: What is the oxidation state of chromium in K2Cr2O7? (2021) 2021
Solution: In K2Cr2O7, the total charge from potassium (K) is +2, and oxygen (O) contributes -14. Let the oxidation state of Cr be x. The equation is 2x - 14 + 2 = 0, solving gives x = +6.
Steps: 8
Step 1: Identify the compound K2Cr2O7. It contains potassium (K), chromium (Cr), and oxygen (O).
Step 2: Determine the oxidation state of potassium (K). Each potassium (K) has an oxidation state of +1. Since there are 2 potassium atoms, the total contribution from potassium is 2 * +1 = +2.
Step 3: Determine the oxidation state of oxygen (O). Each oxygen (O) has an oxidation state of -2. Since there are 7 oxygen atoms, the total contribution from oxygen is 7 * -2 = -14.
Step 4: Let the oxidation state of chromium (Cr) be represented as x. There are 2 chromium atoms, so their total contribution is 2x.
Step 5: Set up the equation based on the total charge of the compound. The equation is: 2x (from Cr) - 14 (from O) + 2 (from K) = 0.
