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What is the oxidation state of chromium in K2Cr2O7? (2021) 2021

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Question: What is the oxidation state of chromium in K2Cr2O7? (2021) 2021

Options:

  1. +3
  2. +6
  3. +2
  4. +5

Correct Answer: +6

Exam Year: 2021

Solution: 

In K2Cr2O7, the total charge from potassium (K) is +2, and oxygen (O) contributes -14. Let the oxidation state of Cr be x. The equation is 2x - 14 + 2 = 0, solving gives x = +6.

What is the oxidation state of chromium in K2Cr2O7? (2021) 2021

Practice Questions

Q1
What is the oxidation state of chromium in K2Cr2O7? (2021) 2021
  1. +3
  2. +6
  3. +2
  4. +5

Questions & Step-by-Step Solutions

What is the oxidation state of chromium in K2Cr2O7? (2021) 2021
  • Step 1: Identify the compound K2Cr2O7. It contains potassium (K), chromium (Cr), and oxygen (O).
  • Step 2: Determine the oxidation state of potassium (K). Each potassium (K) has an oxidation state of +1. Since there are 2 potassium atoms, the total contribution from potassium is 2 * +1 = +2.
  • Step 3: Determine the oxidation state of oxygen (O). Each oxygen (O) has an oxidation state of -2. Since there are 7 oxygen atoms, the total contribution from oxygen is 7 * -2 = -14.
  • Step 4: Let the oxidation state of chromium (Cr) be represented as x. There are 2 chromium atoms, so their total contribution is 2x.
  • Step 5: Set up the equation based on the total charge of the compound. The equation is: 2x (from Cr) - 14 (from O) + 2 (from K) = 0.
  • Step 6: Simplify the equation: 2x - 14 + 2 = 0 becomes 2x - 12 = 0.
  • Step 7: Solve for x: 2x = 12, so x = 12 / 2 = 6.
  • Step 8: Conclude that the oxidation state of chromium (Cr) in K2Cr2O7 is +6.
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