A gas expands from 2 L to 5 L at a constant pressure of 1 atm. How much work is

₹0.0

Question: A gas expands from 2 L to 5 L at a constant pressure of 1 atm. How much work is done by the gas? (2023)

Options:

Correct Answer: 3 L·atm

Solution:

Work done by the gas during expansion at constant pressure is W = PΔV. Here, ΔV = 5 L - 2 L = 3 L, so W = 1 atm * 3 L = 3 L·atm.

A gas expands from 2 L to 5 L at a constant pressure of 1 atm. How much work is done by the gas? (2023)

A gas expands from 2 L to 5 L at a constant pressure of 1 atm. How much work is done by the gas? (2023)

Step 1: Identify the initial volume of the gas, which is 2 L.
Step 2: Identify the final volume of the gas, which is 5 L.
Step 3: Calculate the change in volume (ΔV) by subtracting the initial volume from the final volume: ΔV = 5 L - 2 L.
Step 4: Perform the subtraction: ΔV = 3 L.
Step 5: Identify the constant pressure at which the gas expands, which is 1 atm.
Step 6: Use the formula for work done by the gas during expansion at constant pressure: W = P * ΔV.
Step 7: Substitute the values into the formula: W = 1 atm * 3 L.
Step 8: Calculate the work done: W = 3 L·atm.

Work Done by Gas – The calculation of work done by a gas during expansion or compression, particularly at constant pressure, using the formula W = PΔV.
Units of Measurement – Understanding the units involved in the calculation, specifically the conversion between liters and atmospheres in the context of work.