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What is the phase angle in a circuit with a resistance of 30 ohms and a reactanc
What is the phase angle in a circuit with a resistance of 30 ohms and a reactance of 40 ohms? (2021)
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Practice Questions
1 question
Q1
What is the phase angle in a circuit with a resistance of 30 ohms and a reactance of 40 ohms? (2021)
53.13°
36.87°
45°
60°
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θ = tan⁻¹(X/R) = tan⁻¹(40/30) = 53.13°.
Questions & Step-by-step Solutions
1 item
Q
Q: What is the phase angle in a circuit with a resistance of 30 ohms and a reactance of 40 ohms? (2021)
Solution:
θ = tan⁻¹(X/R) = tan⁻¹(40/30) = 53.13°.
Steps: 6
Show Steps
Step 1: Identify the resistance (R) and reactance (X) values. Here, R = 30 ohms and X = 40 ohms.
Step 2: Use the formula for phase angle θ, which is θ = tan⁻¹(X/R).
Step 3: Substitute the values into the formula: θ = tan⁻¹(40/30).
Step 4: Calculate the value of 40 divided by 30, which is approximately 1.3333.
Step 5: Use a calculator to find the arctangent (tan⁻¹) of 1.3333.
Step 6: The result is approximately 53.13 degrees, which is the phase angle θ.
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