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Evaluate ∫ (2x + 3) dx. (2022)

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Question: Evaluate ∫ (2x + 3) dx. (2022)

Options:

  1. x^2 + 3x + C
  2. x^2 + 3 + C
  3. x^2 + 3x + 1
  4. 2x^2 + 3 + C

Correct Answer: x^2 + 3x + C

Solution:

The integral is (2/2)x^2 + 3x + C = x^2 + 3x + C.

Evaluate ∫ (2x + 3) dx. (2022)

Practice Questions

Q1
Evaluate ∫ (2x + 3) dx. (2022)
  1. x^2 + 3x + C
  2. x^2 + 3 + C
  3. x^2 + 3x + 1
  4. 2x^2 + 3 + C

Questions & Step-by-Step Solutions

Evaluate ∫ (2x + 3) dx. (2022)
  • Step 1: Identify the function to integrate, which is (2x + 3).
  • Step 2: Break the integral into two parts: ∫(2x) dx and ∫(3) dx.
  • Step 3: For the first part, ∫(2x) dx, use the power rule: increase the exponent of x by 1 (from 1 to 2) and divide by the new exponent. This gives (2/2)x^2 = x^2.
  • Step 4: For the second part, ∫(3) dx, since 3 is a constant, multiply it by x. This gives 3x.
  • Step 5: Combine the results from Step 3 and Step 4: x^2 + 3x.
  • Step 6: Add the constant of integration, C, to the final result: x^2 + 3x + C.
  • Integration of Polynomials – The question tests the ability to integrate a polynomial function, specifically applying the power rule for integration.
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