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What is the mass of NaOH required to prepare 0.5 L of a 1 M solution? (2023)
What is the mass of NaOH required to prepare 0.5 L of a 1 M solution? (2023)
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Practice Questions
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Q1
What is the mass of NaOH required to prepare 0.5 L of a 1 M solution? (2023)
20 g
40 g
10 g
30 g
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Molar mass of NaOH = 40 g/mol; grams = moles × molar mass = (1 mole/L × 0.5 L) × 40 g/mol = 20 g
Questions & Step-by-step Solutions
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Q
Q: What is the mass of NaOH required to prepare 0.5 L of a 1 M solution? (2023)
Solution:
Molar mass of NaOH = 40 g/mol; grams = moles × molar mass = (1 mole/L × 0.5 L) × 40 g/mol = 20 g
Steps: 8
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Step 1: Understand that a 1 M (molar) solution means there is 1 mole of solute (NaOH) in 1 liter of solution.
Step 2: Since we want to prepare 0.5 L of a 1 M solution, we need to calculate how many moles of NaOH are needed for 0.5 L.
Step 3: Use the formula: moles = molarity × volume. Here, molarity is 1 mole/L and volume is 0.5 L.
Step 4: Calculate the moles: moles = 1 mole/L × 0.5 L = 0.5 moles of NaOH.
Step 5: Find the molar mass of NaOH, which is 40 g/mol.
Step 6: Now, calculate the mass of NaOH needed using the formula: mass = moles × molar mass.
Step 7: Substitute the values: mass = 0.5 moles × 40 g/mol = 20 grams.
Step 8: Therefore, you need 20 grams of NaOH to prepare 0.5 L of a 1 M solution.
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