If 3 moles of glucose are dissolved in 1 liter of solution, what is the molality of the solution? (2023)

1 question

1 item

Q: If 3 moles of glucose are dissolved in 1 liter of solution, what is the molality of the solution? (2023)

Solution: Molality (m) = moles of solute / kg of solvent; assuming 1 L of water = 1 kg, m = 3 moles / 1 kg = 3 m

Steps: 6

Step 1: Understand what molality means. Molality (m) is a measure of the concentration of a solute in a solution, defined as the number of moles of solute per kilogram of solvent.
Step 2: Identify the amount of solute. In this case, we have 3 moles of glucose.
Step 3: Identify the amount of solvent. We are given that the solution is 1 liter. We assume that 1 liter of water has a mass of approximately 1 kilogram.
Step 4: Use the formula for molality. The formula is: Molality (m) = moles of solute / kg of solvent.
Step 5: Plug in the values into the formula. We have 3 moles of glucose and 1 kg of water, so we calculate: m = 3 moles / 1 kg.
Step 6: Calculate the result. This gives us a molality of 3 m.