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What is the pH of a 0.05 M acetic acid solution (Ka = 1.8 x 10^-5)? (2023)

Practice Questions

1 question
Q1
What is the pH of a 0.05 M acetic acid solution (Ka = 1.8 x 10^-5)? (2023)
  1. 2.9
  2. 3.1
  3. 4.0
  4. 4.7

Questions & Step-by-step Solutions

1 item
Q
Q: What is the pH of a 0.05 M acetic acid solution (Ka = 1.8 x 10^-5)? (2023)
Solution: Using the formula for weak acids, pH = 0.5(pKa - log[C]) where pKa = -log(1.8 x 10^-5) ≈ 4.74. pH = 0.5(4.74 - log(0.05)) ≈ 4.7.
Steps: 0

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