What is the cell potential of a galvanic cell with E° = 1.5 V and Q = 10?
Practice Questions
1 question
Q1
What is the cell potential of a galvanic cell with E° = 1.5 V and Q = 10?
1.2 V
1.0 V
1.3 V
1.4 V
Using the Nernst equation, E = E° - (RT/nF)lnQ, we find E ≈ 1.0 V.
Questions & Step-by-step Solutions
1 item
Q
Q: What is the cell potential of a galvanic cell with E° = 1.5 V and Q = 10?
Solution: Using the Nernst equation, E = E° - (RT/nF)lnQ, we find E ≈ 1.0 V.
Steps: 8
Step 1: Identify the given values. We have E° = 1.5 V and Q = 10.
Step 2: Write down the Nernst equation: E = E° - (RT/nF)lnQ.
Step 3: Determine the constants R, T, n, and F. Use R = 8.314 J/(mol·K), T = 298 K (room temperature), n = number of moles of electrons transferred (assume n = 1 for simplicity), and F = 96485 C/mol.
Step 4: Calculate the term (RT/nF). Substitute the values: (8.314 J/(mol·K) * 298 K) / (1 * 96485 C/mol). This gives approximately 0.0257 V.
