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What is the power output of a motor that does 1200 J of work in 30 seconds?
What is the power output of a motor that does 1200 J of work in 30 seconds?
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Q1
What is the power output of a motor that does 1200 J of work in 30 seconds?
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Power = Work / Time = 1200 J / 30 s = 40 W.
Questions & Step-by-step Solutions
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Q
Q: What is the power output of a motor that does 1200 J of work in 30 seconds?
Solution:
Power = Work / Time = 1200 J / 30 s = 40 W.
Steps: 6
Show Steps
Step 1: Identify the amount of work done by the motor, which is 1200 Joules (J).
Step 2: Identify the time taken to do the work, which is 30 seconds (s).
Step 3: Use the formula for power, which is Power = Work / Time.
Step 4: Substitute the values into the formula: Power = 1200 J / 30 s.
Step 5: Calculate the power: 1200 divided by 30 equals 40.
Step 6: Conclude that the power output of the motor is 40 Watts (W).
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