What is the total current in a circuit with a 15V battery and two 5Ω resistors i

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Question: What is the total current in a circuit with a 15V battery and two 5Ω resistors in series? (2023)

Options:

Correct Answer: 2A

Solution:

Total resistance R = 5Ω + 5Ω = 10Ω; I = V/R = 15V / 10Ω = 1.5A.

What is the total current in a circuit with a 15V battery and two 5Ω resistors in series? (2023)

What is the total current in a circuit with a 15V battery and two 5Ω resistors in series? (2023)

Step 1: Identify the voltage of the battery, which is 15V.
Step 2: Identify the resistance of each resistor, which is 5Ω.
Step 3: Since there are two resistors in series, add their resistances together: 5Ω + 5Ω = 10Ω.
Step 4: Use Ohm's Law to find the current. Ohm's Law states that current (I) equals voltage (V) divided by resistance (R).
Step 5: Substitute the values into the formula: I = 15V / 10Ω.
Step 6: Calculate the current: 15V divided by 10Ω equals 1.5A.

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