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In a circuit with a 9V battery and a 3Ω resistor, what is the power dissipated i
In a circuit with a 9V battery and a 3Ω resistor, what is the power dissipated in the resistor? (2023)
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In a circuit with a 9V battery and a 3Ω resistor, what is the power dissipated in the resistor? (2023)
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Power P = V²/R = (9V)² / 3Ω = 81 / 3 = 27W.
Questions & Step-by-step Solutions
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Q
Q: In a circuit with a 9V battery and a 3Ω resistor, what is the power dissipated in the resistor? (2023)
Solution:
Power P = V²/R = (9V)² / 3Ω = 81 / 3 = 27W.
Steps: 7
Show Steps
Step 1: Identify the voltage (V) from the battery, which is 9 volts.
Step 2: Identify the resistance (R) of the resistor, which is 3 ohms.
Step 3: Use the formula for power (P) dissipated in a resistor, which is P = V² / R.
Step 4: Substitute the values into the formula: P = (9V)² / 3Ω.
Step 5: Calculate (9V)², which is 81.
Step 6: Divide 81 by 3Ω to find the power: 81 / 3 = 27W.
Step 7: Conclude that the power dissipated in the resistor is 27 watts.
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