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In a circuit with a 9V battery and a 3Ω resistor, what is the power dissipated i

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Question: In a circuit with a 9V battery and a 3Ω resistor, what is the power dissipated in the resistor? (2023)

Options:

  1. 3W
  2. 9W
  3. 6W
  4. 12W

Correct Answer: 9W

Solution: 

Power P = V²/R = (9V)² / 3Ω = 81 / 3 = 27W.

In a circuit with a 9V battery and a 3Ω resistor, what is the power dissipated i

Practice Questions

Q1
In a circuit with a 9V battery and a 3Ω resistor, what is the power dissipated in the resistor? (2023)
  1. 3W
  2. 9W
  3. 6W
  4. 12W

Questions & Step-by-Step Solutions

In a circuit with a 9V battery and a 3Ω resistor, what is the power dissipated in the resistor? (2023)
  • Step 1: Identify the voltage (V) from the battery, which is 9 volts.
  • Step 2: Identify the resistance (R) of the resistor, which is 3 ohms.
  • Step 3: Use the formula for power (P) dissipated in a resistor, which is P = V² / R.
  • Step 4: Substitute the values into the formula: P = (9V)² / 3Ω.
  • Step 5: Calculate (9V)², which is 81.
  • Step 6: Divide 81 by 3Ω to find the power: 81 / 3 = 27W.
  • Step 7: Conclude that the power dissipated in the resistor is 27 watts.
  • Ohm's Law and Power Calculation – Understanding the relationship between voltage, resistance, and power in electrical circuits.
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