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In a series RLC circuit, if R = 20Ω, L = 0.1 H, and C = 100μF, what is the reson
In a series RLC circuit, if R = 20Ω, L = 0.1 H, and C = 100μF, what is the resonant frequency? (2020)
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In a series RLC circuit, if R = 20Ω, L = 0.1 H, and C = 100μF, what is the resonant frequency? (2020)
50 Hz
100 Hz
159.15 Hz
200 Hz
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Resonant frequency f₀ = 1 / (2π√(LC)) = 1 / (2π√(0.1 * 100e-6)) = 159.15 Hz.
Questions & Step-by-step Solutions
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Q
Q: In a series RLC circuit, if R = 20Ω, L = 0.1 H, and C = 100μF, what is the resonant frequency? (2020)
Solution:
Resonant frequency f₀ = 1 / (2π√(LC)) = 1 / (2π√(0.1 * 100e-6)) = 159.15 Hz.
Steps: 8
Show Steps
Step 1: Identify the values given in the problem. We have R = 20Ω, L = 0.1 H, and C = 100μF.
Step 2: Convert the capacitance from microfarads to farads. 100μF = 100 * 10^-6 F = 0.0001 F.
Step 3: Use the formula for resonant frequency: f₀ = 1 / (2π√(LC)).
Step 4: Substitute the values of L and C into the formula: f₀ = 1 / (2π√(0.1 * 0.0001)).
Step 5: Calculate the product of L and C: 0.1 * 0.0001 = 0.00001.
Step 6: Find the square root of 0.00001: √(0.00001) = 0.003162.
Step 7: Multiply by 2π: 2π * 0.003162 ≈ 0.01987.
Step 8: Take the reciprocal to find the resonant frequency: f₀ = 1 / 0.01987 ≈ 50.31 Hz.
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