In an AC circuit, if the voltage is given by V(t) = 100√2 sin(1000t), what is th

In an AC circuit, if the voltage is given by V(t) = 100√2 sin(1000t), what is the peak voltage? (2023)

In an AC circuit, if the voltage is given by V(t) = 100√2 sin(1000t), what is the peak voltage? (2023)

Step 1: Identify the given voltage function, which is V(t) = 100√2 sin(1000t).
Step 2: Understand that in the function V(t), the term 'sin' indicates that this is an AC voltage function.
Step 3: Recognize that the peak voltage in a sine function is determined by the coefficient in front of the 'sin' term.
Step 4: Look at the coefficient of the 'sin' term in the function, which is 100√2.
Step 5: Conclude that the peak voltage is equal to this coefficient, which is 100√2.

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