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What is the particular solution of dy/dx = 4y with the initial condition y(0) = 2?

Practice Questions

1 question
Q1
What is the particular solution of dy/dx = 4y with the initial condition y(0) = 2?
  1. y = 2e^(4x)
  2. y = e^(4x)
  3. y = 4e^(4x)
  4. y = 2e^(x)

Questions & Step-by-step Solutions

1 item
Q
Q: What is the particular solution of dy/dx = 4y with the initial condition y(0) = 2?
Solution: The general solution is y = Ce^(4x). Using the initial condition y(0) = 2, we find C = 2, thus y = 2e^(4x).
Steps: 0

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