What is the particular solution of dy/dx = 4y with the initial condition y(0) =

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Question: What is the particular solution of dy/dx = 4y with the initial condition y(0) = 2?

Options:

Correct Answer: y = 2e^(4x)

Solution:

The general solution is y = Ce^(4x). Using the initial condition y(0) = 2, we find C = 2, thus y = 2e^(4x).

What is the particular solution of dy/dx = 4y with the initial condition y(0) = 2?

What is the particular solution of dy/dx = 4y with the initial condition y(0) = 2?

Step 1: Start with the differential equation dy/dx = 4y.
Step 2: Recognize that this is a separable equation, which means we can separate the variables y and x.
Step 3: Rewrite the equation as dy/y = 4 dx.
Step 4: Integrate both sides. The left side becomes ln|y| and the right side becomes 4x + C, where C is a constant.
Step 5: After integrating, we have ln|y| = 4x + C.
Step 6: Exponentiate both sides to solve for y. This gives us y = e^(4x + C).
Step 7: Rewrite e^(4x + C) as y = e^(4x) * e^C. Let C' = e^C, so y = C'e^(4x).
Step 8: The general solution is y = Ce^(4x), where C is a constant.
Step 9: Use the initial condition y(0) = 2 to find the value of C. Substitute x = 0 into the general solution: y(0) = Ce^(4*0) = C.
Step 10: Set C equal to 2 because y(0) = 2. So, C = 2.
Step 11: Substitute C back into the general solution: y = 2e^(4x).
Step 12: The particular solution is y = 2e^(4x).

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