What is the mass of solute in grams required to make 1 L of a 0.5 M NaOH solutio

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Question: What is the mass of solute in grams required to make 1 L of a 0.5 M NaOH solution? (2021)

Options:

Correct Answer: 40 g

Solution:

Molar mass of NaOH = 40 g/mol. Mass = moles × molar mass = 0.5 moles × 40 g/mol = 20 g.

What is the mass of solute in grams required to make 1 L of a 0.5 M NaOH solution? (2021)

What is the mass of solute in grams required to make 1 L of a 0.5 M NaOH solution? (2021)

Step 1: Understand that Molarity (M) is defined as moles of solute per liter of solution.
Step 2: Identify the desired molarity of the solution, which is 0.5 M.
Step 3: Determine the volume of the solution, which is 1 L.
Step 4: Calculate the number of moles of solute needed using the formula: Moles = Molarity × Volume.
Step 5: Substitute the values: Moles = 0.5 M × 1 L = 0.5 moles.
Step 6: Find the molar mass of NaOH, which is 40 g/mol.
Step 7: Calculate the mass of the solute using the formula: Mass = Moles × Molar Mass.
Step 8: Substitute the values: Mass = 0.5 moles × 40 g/mol = 20 g.

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