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Identify the oxidizing agent in the reaction: 2H2 + O2 β†’ 2H2O. (2023)

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Question: Identify the oxidizing agent in the reaction: 2H2 + O2 β†’ 2H2O. (2023)

Options:

  1. H2
  2. O2
  3. H2O
  4. None of the above

Correct Answer: O2

Solution:

O2 is the oxidizing agent as it gains electrons and is reduced to H2O.

Identify the oxidizing agent in the reaction: 2H2 + O2 β†’ 2H2O. (2023)

Practice Questions

Q1
Identify the oxidizing agent in the reaction: 2H2 + O2 β†’ 2H2O. (2023)
  1. H2
  2. O2
  3. H2O
  4. None of the above

Questions & Step-by-Step Solutions

Identify the oxidizing agent in the reaction: 2H2 + O2 β†’ 2H2O. (2023)
  • Step 1: Look at the reaction: 2H2 + O2 β†’ 2H2O.
  • Step 2: Identify the substances involved: H2 (hydrogen) and O2 (oxygen).
  • Step 3: Determine what happens to each substance during the reaction.
  • Step 4: Notice that H2 is turning into H2O, which means it is losing electrons.
  • Step 5: Recognize that O2 is turning into H2O, which means it is gaining electrons.
  • Step 6: Understand that the substance that gains electrons is called the oxidizing agent.
  • Step 7: Conclude that O2 is the oxidizing agent because it gains electrons and is reduced to H2O.
  • Oxidizing Agent – An oxidizing agent is a substance that gains electrons in a chemical reaction, causing another substance to be oxidized.
  • Reduction and Oxidation – Reduction refers to the gain of electrons, while oxidation refers to the loss of electrons in a chemical reaction.
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