What is the pH of a 0.001 M acetic acid solution (Ka = 1.8 x 10^-5)?

Practice Questions

Q1
What is the pH of a 0.001 M acetic acid solution (Ka = 1.8 x 10^-5)?
  1. 2.87
  2. 3.87
  3. 4.87
  4. 5.87

Questions & Step-by-Step Solutions

What is the pH of a 0.001 M acetic acid solution (Ka = 1.8 x 10^-5)?
  • Step 1: Identify the concentration of acetic acid (C) which is given as 0.001 M.
  • Step 2: Calculate the pKa from the given Ka value. pKa = -log(Ka) = -log(1.8 x 10^-5).
  • Step 3: Use a calculator to find pKa. pKa ≈ 4.74.
  • Step 4: Use the formula for weak acids to find pH: pH = 0.5(pKa - logC).
  • Step 5: Substitute the values into the formula: pH = 0.5(4.74 - log(0.001)).
  • Step 6: Calculate log(0.001), which is -3.
  • Step 7: Substitute -3 into the formula: pH = 0.5(4.74 - (-3)).
  • Step 8: Simplify the equation: pH = 0.5(4.74 + 3) = 0.5(7.74).
  • Step 9: Calculate the final pH: pH = 3.87.
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