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In a reaction, if the concentration of reactant A is halved, and the rate consta

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Question: In a reaction, if the concentration of reactant A is halved, and the rate constant remains the same, how does the rate change for a first-order reaction? (2021)

Options:

  1. Doubles
  2. Halves
  3. Remains the same
  4. Quadruples

Correct Answer: Halves

Solution: 

For a first-order reaction, if [A] is halved, the rate also halves.

In a reaction, if the concentration of reactant A is halved, and the rate consta

Practice Questions

Q1
In a reaction, if the concentration of reactant A is halved, and the rate constant remains the same, how does the rate change for a first-order reaction? (2021)
  1. Doubles
  2. Halves
  3. Remains the same
  4. Quadruples

Questions & Step-by-Step Solutions

In a reaction, if the concentration of reactant A is halved, and the rate constant remains the same, how does the rate change for a first-order reaction? (2021)
  • Step 1: Understand that a first-order reaction means the rate depends on the concentration of one reactant, A.
  • Step 2: Write the rate equation for a first-order reaction: Rate = k[A], where k is the rate constant.
  • Step 3: If the concentration of A is halved, it becomes [A]/2.
  • Step 4: Substitute [A]/2 into the rate equation: Rate = k([A]/2).
  • Step 5: Simplify the equation: Rate = (k[A])/2, which shows that the new rate is half of the original rate.
  • Step 6: Conclude that if the concentration of A is halved, the rate of the reaction also halves.
  • First-Order Reaction Kinetics – In a first-order reaction, the rate of reaction is directly proportional to the concentration of one reactant.
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