In a reaction, if the concentration of reactant A is halved, and the rate consta
Practice Questions
Q1
In a reaction, if the concentration of reactant A is halved, and the rate constant remains the same, how does the rate change for a first-order reaction? (2021)
Doubles
Halves
Remains the same
Quadruples
Questions & Step-by-Step Solutions
In a reaction, if the concentration of reactant A is halved, and the rate constant remains the same, how does the rate change for a first-order reaction? (2021)
Step 1: Understand that a first-order reaction means the rate depends on the concentration of one reactant, A.
Step 2: Write the rate equation for a first-order reaction: Rate = k[A], where k is the rate constant.
Step 3: If the concentration of A is halved, it becomes [A]/2.
Step 4: Substitute [A]/2 into the rate equation: Rate = k([A]/2).
Step 5: Simplify the equation: Rate = (k[A])/2, which shows that the new rate is half of the original rate.
Step 6: Conclude that if the concentration of A is halved, the rate of the reaction also halves.
