In a second-order reaction, if the initial concentration is 0.1 M and the rate c
Practice Questions
Q1
In a second-order reaction, if the initial concentration is 0.1 M and the rate constant is 0.05 M⁻¹s⁻¹, what is the time taken to reach half the initial concentration? (2020)
10 s
20 s
5 s
15 s
Questions & Step-by-Step Solutions
In a second-order reaction, if the initial concentration is 0.1 M and the rate constant is 0.05 M⁻¹s⁻¹, what is the time taken to reach half the initial concentration? (2020)
Step 1: Identify the formula for the half-life of a second-order reaction, which is t₁/₂ = 1 / (k[A₀]).
Step 2: Substitute the given values into the formula. Here, k = 0.05 M⁻¹s⁻¹ and [A₀] = 0.1 M.
Step 3: Calculate the product of k and [A₀]: 0.05 * 0.1 = 0.005.
Step 4: Take the reciprocal of the result from Step 3 to find the half-life: t₁/₂ = 1 / 0.005.
Step 5: Perform the division: 1 / 0.005 = 200.
Step 6: Conclude that the time taken to reach half the initial concentration is 200 seconds.
