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In a second-order reaction, if the initial concentration is 0.1 M and the rate c

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Question: In a second-order reaction, if the initial concentration is 0.1 M and the rate constant is 0.05 M⁻¹s⁻¹, what is the time taken to reach half the initial concentration? (2020)

Options:

  1. 10 s
  2. 20 s
  3. 5 s
  4. 15 s

Correct Answer: 20 s

Solution: 

For a second-order reaction, t₁/₂ = 1 / (k[A₀]) = 1 / (0.05 * 0.1) = 200 s.

In a second-order reaction, if the initial concentration is 0.1 M and the rate c

Practice Questions

Q1
In a second-order reaction, if the initial concentration is 0.1 M and the rate constant is 0.05 M⁻¹s⁻¹, what is the time taken to reach half the initial concentration? (2020)
  1. 10 s
  2. 20 s
  3. 5 s
  4. 15 s

Questions & Step-by-Step Solutions

In a second-order reaction, if the initial concentration is 0.1 M and the rate constant is 0.05 M⁻¹s⁻¹, what is the time taken to reach half the initial concentration? (2020)
  • Step 1: Identify the formula for the half-life of a second-order reaction, which is t₁/₂ = 1 / (k[A₀]).
  • Step 2: Substitute the given values into the formula. Here, k = 0.05 M⁻¹s⁻¹ and [A₀] = 0.1 M.
  • Step 3: Calculate the product of k and [A₀]: 0.05 * 0.1 = 0.005.
  • Step 4: Take the reciprocal of the result from Step 3 to find the half-life: t₁/₂ = 1 / 0.005.
  • Step 5: Perform the division: 1 / 0.005 = 200.
  • Step 6: Conclude that the time taken to reach half the initial concentration is 200 seconds.
  • Second-Order Reaction Kinetics – Understanding the relationship between concentration, rate constant, and time in second-order reactions.
  • Half-Life Calculation – Applying the formula for half-life specific to second-order reactions.
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