A machine does 1200 J of work in 60 seconds. What is its efficiency if the input

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Question: A machine does 1200 J of work in 60 seconds. What is its efficiency if the input energy is 2000 J? (2022)

Options:

Correct Answer: 60%

Solution:

Efficiency = (Output Work / Input Energy) * 100 = (1200 J / 2000 J) * 100 = 60%.

A machine does 1200 J of work in 60 seconds. What is its efficiency if the input energy is 2000 J? (2022)

A machine does 1200 J of work in 60 seconds. What is its efficiency if the input energy is 2000 J? (2022)

Step 1: Identify the output work done by the machine, which is 1200 J.
Step 2: Identify the input energy provided to the machine, which is 2000 J.
Step 3: Use the efficiency formula: Efficiency = (Output Work / Input Energy) * 100.
Step 4: Substitute the values into the formula: Efficiency = (1200 J / 2000 J) * 100.
Step 5: Calculate the fraction: 1200 J divided by 2000 J equals 0.6.
Step 6: Multiply 0.6 by 100 to convert it to a percentage: 0.6 * 100 = 60%.
Step 7: Conclude that the efficiency of the machine is 60%.

Efficiency Calculation – Efficiency is calculated by comparing the useful output work to the input energy, expressed as a percentage.
Work and Energy – Understanding the relationship between work done (output) and energy supplied (input) is crucial for solving efficiency problems.