A 15 kg object is lifted to a height of 4 m. What is the work done against gravi
Practice Questions
Q1
A 15 kg object is lifted to a height of 4 m. What is the work done against gravity? (g = 9.8 m/s²) (2021)
588 J
5880 J
392 J
294 J
Questions & Step-by-Step Solutions
A 15 kg object is lifted to a height of 4 m. What is the work done against gravity? (g = 9.8 m/s²) (2021)
Correct Answer: 588 J
Step 1: Identify the mass of the object. In this case, the mass (m) is 15 kg.
Step 2: Identify the height to which the object is lifted. Here, the height (h) is 4 m.
Step 3: Identify the acceleration due to gravity. It is given as g = 9.8 m/s².
Step 4: Use the formula for work done against gravity, which is Work = m * g * h.
Step 5: Substitute the values into the formula: Work = 15 kg * 9.8 m/s² * 4 m.
Step 6: Calculate the result: 15 * 9.8 = 147, then 147 * 4 = 588.
Step 7: Conclude that the work done against gravity is 588 Joules (J).
Work Done Against Gravity – The work done against gravity is calculated using the formula Work = mgh, where m is mass, g is acceleration due to gravity, and h is height.