A tuning fork vibrates at a frequency of 440 Hz. What is the time period of the fork? (2020)
Practice Questions
1 question
Q1
A tuning fork vibrates at a frequency of 440 Hz. What is the time period of the fork? (2020)
0.00227 s
0.0045 s
0.01 s
0.005 s
Time period T = 1/f = 1/440 Hz ≈ 0.00227 s.
Questions & Step-by-step Solutions
1 item
Q
Q: A tuning fork vibrates at a frequency of 440 Hz. What is the time period of the fork? (2020)
Solution: Time period T = 1/f = 1/440 Hz ≈ 0.00227 s.
Steps: 5
Step 1: Understand that frequency (f) is how many times something happens in one second. In this case, the tuning fork vibrates 440 times in one second.
Step 2: The time period (T) is the time it takes for one complete vibration. It is the inverse of frequency.
Step 3: Use the formula for time period: T = 1/f.
Step 4: Substitute the frequency into the formula: T = 1/440 Hz.
Step 5: Calculate the time period: T = 1/440, which is approximately 0.00227 seconds.
