A ball is thrown upwards with a velocity of 20 m/s. How high will it go before c

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Question: A ball is thrown upwards with a velocity of 20 m/s. How high will it go before coming to rest? (2023)

Options:

Correct Answer: 30 m

Solution:

Using the formula h = v²/(2g), where g = 10 m/s², h = (20 m/s)² / (2 * 10 m/s²) = 20 m.

A ball is thrown upwards with a velocity of 20 m/s. How high will it go before coming to rest? (2023)

A ball is thrown upwards with a velocity of 20 m/s. How high will it go before coming to rest? (2023)

Step 1: Identify the initial velocity of the ball, which is 20 m/s.
Step 2: Identify the acceleration due to gravity, which is approximately 10 m/s² (this is the value we will use).
Step 3: Use the formula for maximum height, h = v² / (2g).
Step 4: Substitute the values into the formula: h = (20 m/s)² / (2 * 10 m/s²).
Step 5: Calculate (20 m/s)², which equals 400 m²/s².
Step 6: Calculate 2 * 10 m/s², which equals 20 m/s².
Step 7: Divide 400 m²/s² by 20 m/s² to find h: 400 m²/s² / 20 m/s² = 20 m.
Step 8: Conclude that the maximum height the ball will reach is 20 meters.

Kinematics – The study of motion, particularly the equations that describe the motion of objects under the influence of gravity.
Energy Conservation – Understanding the conversion of kinetic energy to potential energy as the ball rises.