What is the work done when 1 mole of an ideal gas expands isothermally from 10 L
Practice Questions
Q1
What is the work done when 1 mole of an ideal gas expands isothermally from 10 L to 20 L at 300 K? (2022)
300 J
600 J
150 J
0 J
Questions & Step-by-Step Solutions
What is the work done when 1 mole of an ideal gas expands isothermally from 10 L to 20 L at 300 K? (2022)
Step 1: Identify the formula for work done during isothermal expansion of an ideal gas: W = nRT ln(Vf/Vi).
Step 2: Determine the values needed for the formula: n (number of moles) = 1, R (ideal gas constant) = 8.314 J/(mol·K), T (temperature) = 300 K, Vf (final volume) = 20 L, and Vi (initial volume) = 10 L.
Step 3: Plug the values into the formula: W = 1 * 8.314 * 300 * ln(20/10).
Step 4: Calculate the natural logarithm: ln(20/10) = ln(2).
Step 5: Calculate the work done: W = 1 * 8.314 * 300 * ln(2).
Step 6: Use a calculator to find ln(2) which is approximately 0.693.
Step 7: Multiply the values: W = 1 * 8.314 * 300 * 0.693.
