What is the final temperature when 200 g of ice at 0°C is added to 100 g of wate

What is the final temperature when 200 g of ice at 0°C is added to 100 g of water at 80°C? (Assume no heat loss to the surroundings) (2023)

What is the final temperature when 200 g of ice at 0°C is added to 100 g of water at 80°C? (Assume no heat loss to the surroundings) (2023)

Step 1: Identify the mass of ice and water. We have 200 g of ice and 100 g of water.
Step 2: Note the initial temperatures. The ice is at 0°C and the water is at 80°C.
Step 3: Understand that when ice is added to water, heat will transfer from the water to the ice until they reach the same final temperature.
Step 4: Use the formula for heat balance: the heat lost by the water equals the heat gained by the ice.
Step 5: The heat gained by the ice is calculated using the formula: m_ice * L_f, where L_f is the latent heat of fusion for ice.
Step 6: The heat lost by the water is calculated using the formula: m_water * c * (T_final - 80), where c is the specific heat capacity of water.
Step 7: Set up the equation: m_ice * L_f + m_water * c * (T_final - 80) = 0.
Step 8: Substitute the values into the equation and solve for T_final.
Step 9: After solving, you find that T_final = 20°C.

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