Question: What is the final temperature when 200 g of ice at 0°C is added to 100 g of water at 80°C? (Assume no heat loss to the surroundings) (2023)

Options:

1. 0°C
2. 20°C
3. 40°C
4. 80°C

Correct Answer: 20°C

Solution:

Using heat balance: m_ice * L_f + m_water * c * (T_final - 80) = 0. Solving gives T_final = 20°C.