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If two identical capacitors of 4 µF each are connected in series, what is the eq

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Question: If two identical capacitors of 4 µF each are connected in series, what is the equivalent capacitance?

Options:

  1. 2 µF
  2. 4 µF
  3. 6 µF
  4. 8 µF

Correct Answer: 2 µF

Solution: 

C_eq = 1 / (1/C1 + 1/C2) = 1 / (1/4 + 1/4) = 2 µF.

If two identical capacitors of 4 µF each are connected in series, what is the eq

Practice Questions

Q1
If two identical capacitors of 4 µF each are connected in series, what is the equivalent capacitance?
  1. 2 µF
  2. 4 µF
  3. 6 µF
  4. 8 µF

Questions & Step-by-Step Solutions

If two identical capacitors of 4 µF each are connected in series, what is the equivalent capacitance?
  • Step 1: Identify the values of the capacitors. Here, both capacitors (C1 and C2) are 4 µF.
  • Step 2: Use the formula for equivalent capacitance in series: C_eq = 1 / (1/C1 + 1/C2).
  • Step 3: Substitute the values into the formula: C_eq = 1 / (1/4 + 1/4).
  • Step 4: Calculate the fractions: 1/4 + 1/4 = 2/4.
  • Step 5: Now, substitute back into the formula: C_eq = 1 / (2/4).
  • Step 6: Simplify the equation: C_eq = 1 / (0.5) = 2 µF.
  • Capacitance in Series – When capacitors are connected in series, the equivalent capacitance is found using the formula 1/C_eq = 1/C1 + 1/C2.
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