A parallel plate capacitor has a capacitance of 5 µF. If the potential differenc

Practice Questions

A parallel plate capacitor has a capacitance of 5 µF. If the potential difference across it is increased from 10 V to 20 V, what is the change in stored energy?

25 µJ
50 µJ
75 µJ
100 µJ

Questions & Step-by-Step Solutions

A parallel plate capacitor has a capacitance of 5 µF. If the potential difference across it is increased from 10 V to 20 V, what is the change in stored energy?

Step 1: Identify the formula for the energy stored in a capacitor, which is U = 1/2 C V^2.
Step 2: Note the given values: capacitance C = 5 µF (which is 5 × 10^-6 F) and initial voltage V1 = 10 V.
Step 3: Calculate the initial energy (U1) using the formula: U1 = 1/2 * C * V1^2.
Step 4: Substitute the values into the formula: U1 = 1/2 * 5 × 10^-6 * (10)^2.
Step 5: Calculate U1: U1 = 1/2 * 5 × 10^-6 * 100 = 0.025 J.
Step 6: Now, note the final voltage V2 = 20 V.
Step 7: Calculate the final energy (U2) using the same formula: U2 = 1/2 * C * V2^2.
Step 8: Substitute the values into the formula: U2 = 1/2 * 5 × 10^-6 * (20)^2.
Step 9: Calculate U2: U2 = 1/2 * 5 × 10^-6 * 400 = 0.1 J.
Step 10: Find the change in stored energy by subtracting the initial energy from the final energy: Change = U2 - U1.
Step 11: Substitute the values: Change = 0.1 J - 0.025 J.
Step 12: Calculate the change: Change = 0.075 J.
Step 13: Convert the change in energy to microjoules: 0.075 J = 75 µJ.

Capacitance and Energy Storage – Understanding how capacitance relates to energy stored in a capacitor, using the formula U = 1/2 C V^2.
Potential Difference – Recognizing the effect of changing the potential difference on the energy stored in a capacitor.

A parallel plate capacitor has a capacitance of 5 µF. If the potential differenc

Practice Questions

Questions & Step-by-Step Solutions

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