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What is the capacitance of a capacitor that stores 10 µC of charge at a potentia

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Question: What is the capacitance of a capacitor that stores 10 µC of charge at a potential difference of 5 V?

Options:

  1. 2 µF
  2. 5 µF
  3. 10 µF
  4. 20 µF

Correct Answer: 2 µF

Solution: 

C = Q/V = 10 × 10^-6 C / 5 V = 2 × 10^-6 F = 2 µF.

What is the capacitance of a capacitor that stores 10 µC of charge at a potentia

Practice Questions

Q1
What is the capacitance of a capacitor that stores 10 µC of charge at a potential difference of 5 V?
  1. 2 µF
  2. 5 µF
  3. 10 µF
  4. 20 µF

Questions & Step-by-Step Solutions

What is the capacitance of a capacitor that stores 10 µC of charge at a potential difference of 5 V?
  • Step 1: Identify the formula for capacitance, which is C = Q / V.
  • Step 2: Identify the values given in the question: Q (charge) is 10 µC and V (voltage) is 5 V.
  • Step 3: Convert the charge from microcoulombs to coulombs: 10 µC = 10 × 10^-6 C.
  • Step 4: Substitute the values into the formula: C = (10 × 10^-6 C) / (5 V).
  • Step 5: Perform the division: C = 2 × 10^-6 F.
  • Step 6: Convert the capacitance back to microfarads: 2 × 10^-6 F = 2 µF.
  • Capacitance – Capacitance is defined as the ability of a capacitor to store charge per unit voltage, calculated using the formula C = Q/V.
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