A charge of +4 µC is placed in a uniform electric field of strength 500 N/C. Wha
Practice Questions
Q1
A charge of +4 µC is placed in a uniform electric field of strength 500 N/C. What is the work done in moving the charge 0.2 m in the direction of the field?
400 J
200 J
100 J
50 J
Questions & Step-by-Step Solutions
A charge of +4 µC is placed in a uniform electric field of strength 500 N/C. What is the work done in moving the charge 0.2 m in the direction of the field?
Step 1: Identify the charge value, which is +4 µC (microcoulombs). Convert this to coulombs: 4 µC = 4 × 10^-6 C.
Step 2: Identify the strength of the electric field, which is 500 N/C (newtons per coulomb).
Step 3: Identify the distance the charge is moved, which is 0.2 m (meters).
Step 4: Calculate the force (F) acting on the charge using the formula: F = E * q, where E is the electric field strength and q is the charge. So, F = 500 N/C * 4 × 10^-6 C.
Step 5: Calculate the force: F = 500 * 4 × 10^-6 = 0.002 N (newtons).
Step 6: Use the formula for work done (W): W = F * d, where F is the force and d is the distance moved. Substitute the values: W = 0.002 N * 0.2 m.
Step 7: Calculate the work done: W = 0.002 * 0.2 = 0.0004 J (joules).
Step 8: Convert 0.0004 J to a more readable format: 0.0004 J = 0.4 J.
Electric Field and Work – Understanding how work is calculated in an electric field using the formula W = F * d, where F is the force on the charge and d is the distance moved.
Force on a Charge in an Electric Field – Calculating the force exerted on a charge in an electric field using F = E * q, where E is the electric field strength and q is the charge.
