If the electric field at a point is 1000 N/C and the charge at that point is 5 µC, what is the force experienced by the charge?
Practice Questions
1 question
Q1
If the electric field at a point is 1000 N/C and the charge at that point is 5 µC, what is the force experienced by the charge?
0.005 N
0.05 N
0.5 N
5 N
F = E * q = 1000 N/C * 5 × 10^-6 C = 0.005 N.
Questions & Step-by-step Solutions
1 item
Q
Q: If the electric field at a point is 1000 N/C and the charge at that point is 5 µC, what is the force experienced by the charge?
Solution: F = E * q = 1000 N/C * 5 × 10^-6 C = 0.005 N.
Steps: 6
Step 1: Understand the formula for force (F) experienced by a charge in an electric field. The formula is F = E * q, where E is the electric field strength and q is the charge.
Step 2: Identify the values given in the question. The electric field (E) is 1000 N/C and the charge (q) is 5 µC.
Step 3: Convert the charge from microcoulombs (µC) to coulombs (C). 5 µC is equal to 5 × 10^-6 C.
Step 4: Substitute the values into the formula. F = 1000 N/C * 5 × 10^-6 C.
Step 5: Calculate the force. Multiply 1000 by 5 × 10^-6 to get 0.005 N.
Step 6: Conclude that the force experienced by the charge is 0.005 N.
