Find the value of k if the equation x² + kx + 16 = 0 has no real roots. (2022)

Practice Questions

Q1
Find the value of k if the equation x² + kx + 16 = 0 has no real roots. (2022)
  1. k < 8
  2. k > 8
  3. k < 0
  4. k > 0

Questions & Step-by-Step Solutions

Find the value of k if the equation x² + kx + 16 = 0 has no real roots. (2022)
  • Step 1: Identify the equation given, which is x² + kx + 16 = 0.
  • Step 2: Understand that for a quadratic equation to have no real roots, the discriminant must be less than zero.
  • Step 3: Recall the formula for the discriminant, which is D = b² - 4ac, where a, b, and c are the coefficients from the equation ax² + bx + c.
  • Step 4: In our equation, a = 1, b = k, and c = 16.
  • Step 5: Substitute the values into the discriminant formula: D = k² - 4*1*16.
  • Step 6: Simplify the expression: D = k² - 64.
  • Step 7: Set up the inequality for no real roots: k² - 64 < 0.
  • Step 8: Rearrange the inequality: k² < 64.
  • Step 9: Take the square root of both sides: |k| < 8.
  • Step 10: This means k must be between -8 and 8, so k > 8 or k < -8.
  • Discriminant – The discriminant of a quadratic equation determines the nature of its roots; if it is less than zero, the equation has no real roots.
  • Quadratic Equation – A quadratic equation is in the form ax² + bx + c = 0, where a, b, and c are constants.
  • Inequalities – Understanding how to manipulate inequalities is crucial for determining the range of values for k.
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