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If 50 mL of a 3 M solution is diluted to 200 mL, what is the new molarity? (2020
If 50 mL of a 3 M solution is diluted to 200 mL, what is the new molarity? (2020)
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Q1
If 50 mL of a 3 M solution is diluted to 200 mL, what is the new molarity? (2020)
0.75 M
1.5 M
2 M
3 M
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Using M1V1 = M2V2, (3 M)(50 mL) = M2(200 mL) => M2 = (3 M × 50 mL) / 200 mL = 0.75 M.
Questions & Step-by-step Solutions
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Q
Q: If 50 mL of a 3 M solution is diluted to 200 mL, what is the new molarity? (2020)
Solution:
Using M1V1 = M2V2, (3 M)(50 mL) = M2(200 mL) => M2 = (3 M × 50 mL) / 200 mL = 0.75 M.
Steps: 8
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Step 1: Identify the initial molarity (M1) and volume (V1) of the solution. Here, M1 = 3 M and V1 = 50 mL.
Step 2: Identify the final volume (V2) after dilution. Here, V2 = 200 mL.
Step 3: Use the dilution formula M1V1 = M2V2, where M2 is the new molarity we want to find.
Step 4: Substitute the known values into the formula: (3 M)(50 mL) = M2(200 mL).
Step 5: Calculate the left side: 3 M × 50 mL = 150 M·mL.
Step 6: Set up the equation: 150 M·mL = M2(200 mL).
Step 7: Solve for M2 by dividing both sides by 200 mL: M2 = 150 M·mL / 200 mL.
Step 8: Calculate M2: M2 = 0.75 M.
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