If the concentration of a reactant is tripled in a second-order reaction, how do

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Question: If the concentration of a reactant is tripled in a second-order reaction, how does the rate change? (2023)

Options:

Correct Answer: Increases by 9 times

Solution:

For a second-order reaction, if concentration is tripled, the rate increases by 3² = 9 times.

If the concentration of a reactant is tripled in a second-order reaction, how does the rate change? (2023)

If the concentration of a reactant is tripled in a second-order reaction, how does the rate change? (2023)

Step 1: Understand that a second-order reaction means the rate of the reaction depends on the square of the concentration of the reactant.
Step 2: Write the rate equation for a second-order reaction, which is Rate = k[A]², where [A] is the concentration of the reactant and k is the rate constant.
Step 3: If the concentration [A] is tripled, it becomes 3[A].
Step 4: Substitute 3[A] into the rate equation: Rate = k(3[A])².
Step 5: Calculate (3[A])², which is 9[A]².
Step 6: This means the new rate is Rate = k(9[A]²), which is 9 times the original rate.

Second-Order Reaction Kinetics – In a second-order reaction, the rate of reaction is proportional to the square of the concentration of the reactant.