If the concentration of a reactant is tripled in a second-order reaction, how do
Practice Questions
Q1
If the concentration of a reactant is tripled in a second-order reaction, how does the rate change? (2023)
Increases by 3 times
Increases by 6 times
Increases by 9 times
Increases by 12 times
Questions & Step-by-Step Solutions
If the concentration of a reactant is tripled in a second-order reaction, how does the rate change? (2023)
Step 1: Understand that a second-order reaction means the rate of the reaction depends on the square of the concentration of the reactant.
Step 2: Write the rate equation for a second-order reaction, which is Rate = k[A]², where [A] is the concentration of the reactant and k is the rate constant.
Step 3: If the concentration [A] is tripled, it becomes 3[A].
Step 4: Substitute 3[A] into the rate equation: Rate = k(3[A])².
Step 5: Calculate (3[A])², which is 9[A]².
Step 6: This means the new rate is Rate = k(9[A]²), which is 9 times the original rate.
