What is the final concentration when 100 mL of 1 M NaCl is diluted to 500 mL? (2

₹0.0

Question: What is the final concentration when 100 mL of 1 M NaCl is diluted to 500 mL? (2021)

Options:

Correct Answer: 0.5 M

Solution:

Using M1V1 = M2V2, (1 M)(0.1 L) = M2(0.5 L). M2 = 0.2 M.

What is the final concentration when 100 mL of 1 M NaCl is diluted to 500 mL? (2021)

What is the final concentration when 100 mL of 1 M NaCl is diluted to 500 mL? (2021)

Step 1: Identify the initial concentration (M1) and volume (V1) of the NaCl solution. Here, M1 = 1 M and V1 = 100 mL (which is 0.1 L).
Step 2: Identify the final volume (V2) after dilution. Here, V2 = 500 mL (which is 0.5 L).
Step 3: Use the dilution formula M1V1 = M2V2, where M2 is the final concentration we want to find.
Step 4: Substitute the known values into the formula: (1 M)(0.1 L) = M2(0.5 L).
Step 5: Calculate the left side: 1 M * 0.1 L = 0.1 mol.
Step 6: Set up the equation: 0.1 mol = M2 * 0.5 L.
Step 7: Solve for M2 by dividing both sides by 0.5 L: M2 = 0.1 mol / 0.5 L.
Step 8: Calculate M2: M2 = 0.2 M.

No concepts available.