What is the volume of 0.2 M NaOH required to neutralize 0.1 M HCl in 250 mL? (20
Practice Questions
Q1
What is the volume of 0.2 M NaOH required to neutralize 0.1 M HCl in 250 mL? (2020)
125 mL
250 mL
500 mL
100 mL
Questions & Step-by-Step Solutions
What is the volume of 0.2 M NaOH required to neutralize 0.1 M HCl in 250 mL? (2020)
Step 1: Identify the concentrations of the solutions. We have 0.1 M HCl and 0.2 M NaOH.
Step 2: Identify the volume of HCl solution. It is 250 mL, which is equal to 0.25 L.
Step 3: Use the formula M1V1 = M2V2, where M1 is the concentration of HCl, V1 is the volume of HCl, M2 is the concentration of NaOH, and V2 is the volume of NaOH we want to find.
Step 4: Substitute the known values into the formula: (0.1 M)(0.25 L) = (0.2 M)(V2).
Step 5: Calculate the left side: 0.1 M * 0.25 L = 0.025 moles of HCl.
Step 6: Set up the equation: 0.025 moles = (0.2 M)(V2).
Step 7: Solve for V2: V2 = 0.025 moles / 0.2 M.
Step 8: Calculate V2: V2 = 0.125 L.
Step 9: Convert V2 from liters to milliliters: 0.125 L = 125 mL.
