What is the molarity of a solution containing 58.5 g of NaCl in 1 liter of solut

₹0.0

Question: What is the molarity of a solution containing 58.5 g of NaCl in 1 liter of solution? (2021)

Options:

Correct Answer: 1 M

Solution:

Molarity (M) = moles of solute / liters of solution. Moles of NaCl = 58.5 g / 58.5 g/mol = 1 mol. Therefore, M = 1 mol / 1 L = 1 M.

What is the molarity of a solution containing 58.5 g of NaCl in 1 liter of solution? (2021)

What is the molarity of a solution containing 58.5 g of NaCl in 1 liter of solution? (2021)

Step 1: Identify the mass of NaCl in the solution, which is 58.5 grams.
Step 2: Find the molar mass of NaCl. The molar mass is 58.5 g/mol.
Step 3: Calculate the number of moles of NaCl using the formula: moles = mass (g) / molar mass (g/mol). So, moles = 58.5 g / 58.5 g/mol = 1 mol.
Step 4: Identify the volume of the solution, which is 1 liter.
Step 5: Use the molarity formula: Molarity (M) = moles of solute / liters of solution. Here, M = 1 mol / 1 L.
Step 6: Calculate the molarity: M = 1 M.

No concepts available.