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A cyclist accelerates at 3 m/s² for 4 seconds. What is the final velocity if the
A cyclist accelerates at 3 m/s² for 4 seconds. What is the final velocity if the initial velocity is 2 m/s? (2023)
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A cyclist accelerates at 3 m/s² for 4 seconds. What is the final velocity if the initial velocity is 2 m/s? (2023)
10 m/s
11 m/s
14 m/s
20 m/s
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Using v = u + at, we have v = 2 m/s + (3 m/s² * 4 s) = 2 + 12 = 14 m/s.
Questions & Step-by-step Solutions
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Q
Q: A cyclist accelerates at 3 m/s² for 4 seconds. What is the final velocity if the initial velocity is 2 m/s? (2023)
Solution:
Using v = u + at, we have v = 2 m/s + (3 m/s² * 4 s) = 2 + 12 = 14 m/s.
Steps: 7
Show Steps
Step 1: Identify the initial velocity (u). In this case, u = 2 m/s.
Step 2: Identify the acceleration (a). Here, a = 3 m/s².
Step 3: Identify the time (t) for which the cyclist accelerates. In this case, t = 4 seconds.
Step 4: Use the formula for final velocity: v = u + at.
Step 5: Calculate the product of acceleration and time: at = 3 m/s² * 4 s = 12 m/s.
Step 6: Add the initial velocity to the product from Step 5: v = 2 m/s + 12 m/s = 14 m/s.
Step 7: The final velocity of the cyclist is 14 m/s.
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